Math question: Diff. Equations
Apr. 8th, 2005 01:05 am![[personal profile]](https://www.dreamwidth.org/img/silk/identity/user.png){kind=small}
ibnekoG.3.b.iii) Use the formula to come up with the exact initial value (starter) on y[0] that gives the break between the two families
Stay with the same differential equation:
y'[t] = f[t_,y_] = - t^2 + y;
y[0] = starter
y [t] = 2 - 2 * [ExponentialE]^t + starter * [ExponentialE]^t + 2t + t^2
Use this formula to come up with the exact initial value (starter) on y[0] that gives the break between the two families
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Yeah, so how do find the exact initial value that'll give the break between a solution that'll graph upwards, and one that'll graph downwards? I'm pretty sure the answer should be 2, but I'm not sure...
Stay with the same differential equation:
y'[t] = f[t_,y_] = - t^2 + y;
y[0] = starter
y [t] = 2 - 2 * [ExponentialE]^t + starter * [ExponentialE]^t + 2t + t^2
Use this formula to come up with the exact initial value (starter) on y[0] that gives the break between the two families
----
Yeah, so how do find the exact initial value that'll give the break between a solution that'll graph upwards, and one that'll graph downwards? I'm pretty sure the answer should be 2, but I'm not sure...
